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How do I solve this integration Q with u substitution? Halp

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cant be done, need to use geometric substitution. You also might be able to see that the formula of a circle, y²+x²=r² written in function of y is equal to, y = sqrt(r²-x²).

With this information you can see that you're trying to find the area of a half circle with radius 8.
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You can use trig substitution, **x²=64sin²(φ)** i.e. **x = 8sin(φ)**
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This is a direct form. Integral √a²-x²= x/2√a²-x² + a²/2 sininverse(x/a)

Or you can substitute x=8sintheta and solve normaly
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Have you tried anything yet? I would start by setting u equal to everything under the radical.
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You could always split it into 2 integrals, one from -8 to 0 and the second from 0 to 8 and then use U substitution to solve

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