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How can I prove similarity using the AA rule? I'm stuck.

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All right angles are congruent and A = A by reflexive property of congruence
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The only way I used to prove is that angle c and d are right angles. But I need more proof and I don't know how to prove it.
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Don't forget this concept. Profs in Calc 1 love to use this in related rates ladder questions.
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Angle ACB and Angle ADE are both right angles, so they’re both equal to 90 degrees. Angles BAC and EAD both just refer to the angle A, and thus they’re the same. Hence by the AA similarity, Triangles ACB and ADE are similar
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1. Angle a is congruent to angle a; reflexive property
2. Angle BCA is a right angle; given?
3. Angle D is a right angle; given?
4. Angle BCA is congruent to angle D; all right angles are congruent
5. Triangle ABC is similar to triangle AED; AA
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Angle BCA and EDA are both straight, so they are equal. Angle A is a Part of triangle EDA and triangle ABC, so ABC is similar to EDA

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