0 like 0 dislike
0 like 0 dislike
Help please

3 Answers

0 like 0 dislike
0 like 0 dislike
Is this calculus or no? There are multiple ways to approach and justify this and the best way depends on what tools you're allowed to use.
0 like 0 dislike
0 like 0 dislike
You'll need to use calculus for this

P = xy

P = (8-2y)y = 8y - 2y^2

Differentiate now

P' = 8 - 4y

Now to find if this is the maxima or minima, you'll need to get the second order derivative, and if it's negative then it's maxima, if positive then minima

P'' = -4 which is negative. So the value you'll get is the maximum value, not the minimum

Now equate P' to 0 to get the critical points

P' = 8-4y = 0

y = 2

x = 8-2y = 4

These are the real numbers. And the product will be 8, the maximum product
0 like 0 dislike
0 like 0 dislike

>Determine the real numbers x and y satisfying x + 2y = 8 and such that the product P(x, y) = xy is maximized. Give justification that your solution is actually a maximum.



This is a parabola that opens down and has a max. at the vertex: -b/(2a)

f(y)=-2y^2 +8y

vertex: y=-8/(2(-2))=2

Now find x

No related questions found

24.8k questions

103k answers


33.7k users

OhhAskMe is a math solving hub where high school and university students ask and answer loads of math questions, discuss the latest in math, and share their knowledge. It’s 100% free!