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Absolute converging sequence ?
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(-1)^n diverges, normally and absolutely. Usually, we have normally -> absolutely or uniform -> simple convergences
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Hi,

I haven't heard of "absolutely convergent" sequences before. If I had to take a stab at a definition, I'd guess that it means that the differences between successive terms form an absolutely convergent series, but that doesn't make sense for the question you're being asked.

It would be good to have the original source of this question to help track down the definition you're missing.
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