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[Real analysis] Recurrence Relation

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maybe this helps: a\[n-1\]² / (a\[n-1\]² - a\[n-1\]+1) = 1 + (a\[n-1\]-1)/(a\[n-1\]²-a\[n-1\]+1), denom has complex roots lets say x and y (conjugates), convert further to a\[n\] = 1 + (x-1)(x-y)\*(1/a\[n-1\]-x) + (y-1)(y-x)\*(1/a\[n-1\]-y)
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