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how to find the bigger number of 2given numbers with the identity a²-b² = (a-b)*(a+b)

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hint: which one is bigger, sqrt(5)+sqrt(3) or sqrt(15)+sqrt(13)?
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You can rearrange the identity to a-b=(a^(2)-b^(2))/(a+b)

So doing this, √5-√3 = 2/(√5+√3) and √15-√13 = 2/(√15+√13).
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Hint: sqrt(a)-sqrt(b) = (a-b)/(sqrt(a)+sqrt(b))

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