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It's very simple but I need some help
ActiviaFrance
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Jun 21
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It's very simple but I need some help
learnmath
ActiviaFrance
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0<= |x_n-y_n| <= |x_n| + |y_n|
Now take limits
In fact, something stronger can be shown. If xn—>x and yn—>y, then d(xn,yn)—>d(x,y).
RoyalLondonCup
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Jun 21
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RoyalLondonCup
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