0 like 0 dislike
0 like 0 dislike
how to get the equation of a right angle bisector line?

3 Answers

0 like 0 dislike
0 like 0 dislike
Make it into y = mx + b form if you like

What is the slope of the perpendicular line?

You can then find the angle bisector as the 45 degree line.
0 like 0 dislike
0 like 0 dislike
If you choose appropriate directions, the angle between a vector on ax+by+c=0 (you know what this looks like) and another vector on the bisector should be 45 degrees. Note that the length of the vectors doesn’t matter here. Using dot product you can solve for the vector on the bisector, which determines the direction of the bisector. Find a point on the bisector and use it to write a parametric equation for the bisector. Transform that to normal equation.
0 like 0 dislike
0 like 0 dislike
When to use the positive value or negative value?

Related questions

0 like 0 dislike
0 like 0 dislike
2 answers
driveshift asked Jun 21
I did this all wrong but got the right answer? Took half of .075, used d=(1+i)/i to get discount rate, and just added. Decimal was off, but i got the numbers right. Luck?...
driveshift asked Jun 21
0 like 0 dislike
0 like 0 dislike
4 answers
RefJK asked Jun 21
I need help with this proof of the recurrence relation for binomial coefficients, I don't get how the author got from green to red
RefJK asked Jun 21
by RefJK
0 like 0 dislike
0 like 0 dislike
3 answers
CormacComedy asked Jun 21
What's wrong with Integrating rings to get the surface area of a sphere.
CormacComedy asked Jun 21
0 like 0 dislike
0 like 0 dislike
2 answers
ZAKIALSALEH asked Jun 21
Given a list of strings enumerated over a finite alphabet, what's the most efficient way to get a string by its index?
ZAKIALSALEH asked Jun 21
0 like 0 dislike
0 like 0 dislike
2 answers
thebandapp asked Jun 21
If you subscribe to a service that is £100 a year for a 5 year term, and you also get £50 sign up discount and one year free, which of the following do you pay?
thebandapp asked Jun 21

24.8k questions

103k answers

0 comments

33.7k users

OhhAskMe is a math solving hub where high school and university students ask and answer loads of math questions, discuss the latest in math, and share their knowledge. It’s 100% free!