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if (3a + 3/a)^2 = 9,then-

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Hint: first step, expand using (x+y)^(2) = x^(2)+2xy+y^(2)
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When the 3 is factored out, the square also applies to it. (ab)\^2 = a\^2b\^2 not a(b\^2)
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>if (3a + 3/a)^2 = 9

Take the square root of both sides:

3a+3/a=+/-3

Divide both sides by 3:

a+1/a=+/-1
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(3a + 3/a)^2 = 9

(3a+3/a)(3a+3/a)=9

Divide both sides by 3:

(a+1/a))(3a+3/a)=3

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