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[Grade 12 Calculus] Help with an integral question please!

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I haven’t tried this problem myself, but try graphing the region you’re trying to analyze. A visualization will help you with the bounds.
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So 8x-(2/3)x^(2) from 6 to 3, plus (2/3)x^2 from 0 to 3.

(48-24)-(24-6)+6?
by
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8x- x^2 2/3 gives you 48-24 -(24-6)=24-18=6

4x/3 -> 2x^2 /3 gives you 6-0=6

add them and get 12 :)
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Those are all straight lines, and no two of them are parallel, so the region must be a triangle. Use the surveyor’s formula.

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