Question

[Grade 12 Calculus] Help with an integral question please!

Answer 1

I haven’t tried this problem myself, but try graphing the region you’re trying to analyze. A visualization will help you with the bounds.

Answer 2

So 8x-(2/3)x^(2) from 6 to 3, plus (2/3)x^2 from 0 to 3.

(48-24)-(24-6)+6?

Answer 3

8x- x^2 2/3 gives you 48-24 -(24-6)=24-18=6

4x/3 -> 2x^2 /3 gives you 6-0=6

add them and get 12 :)

Answer 4

Those are all straight lines, and no two of them are parallel, so the region must be a triangle. Use the surveyor’s formula.