0 like 0 dislike
0 like 0 dislike
Is there any reason to believe that big unsolved conjectures are either provable / disprovable in ZFC?

3 Answers

0 like 0 dislike
0 like 0 dislike
is it reasonable to assume they are provable/disprovable? Yes, because they certainly *seem* true and similar statements are actually provable/disprovable.

Is it possible they are independent  of ZFC? Of course.
0 like 0 dislike
0 like 0 dislike
I've heard that quite a few knowledgeable people think that P = NP is undecidable. That it it false is very unlikely, but it seems like (and I say that as an outsider) more people start to think that it isn't necessarily true either.
0 like 0 dislike
0 like 0 dislike
There's not a lot of reason to think the are or aren't independent.  


There is a compelling reason to think they won't be *proven* independent, which is that no one has any idea how to prove that these statements are independent that are a fraction as plausible as the ideas people have for how to prove them.

Related questions

0 like 0 dislike
0 like 0 dislike
11 answers
phillyvictor asked Jun 21
Can any number theorists explain the patterns going on in this factorization? (Sorta relevant to cyclotomic polynomials.)
phillyvictor asked Jun 21
0 like 0 dislike
0 like 0 dislike
10 answers
0 like 0 dislike
0 like 0 dislike
59 answers
timor_sv asked Jun 21
Got about a free 50-60 days before joining my PhD. Any advice or suggestions on what to do in this free time ?
timor_sv asked Jun 21
0 like 0 dislike
0 like 0 dislike
18 answers
LillyTrials asked Jun 21
Can a special case be generalized in more ways than one? Any well known examples?
LillyTrials asked Jun 21
0 like 0 dislike
0 like 0 dislike
62 answers
VivianBala asked Jun 21
Do any of you guys dream about your math work in your head? OR just math in general?
VivianBala asked Jun 21

24.8k questions

103k answers

0 comments

33.7k users

OhhAskMe is a math solving hub where high school and university students ask and answer loads of math questions, discuss the latest in math, and share their knowledge. It’s 100% free!