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[Discrete Mathematics) Give 5 different forms of the proposition: p → (q ⋁ s)
RAIDERS_PR
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Jan 25
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Logical equivalence
I'm only able to get 3.
≡ ¬p ⋁ (q ⋁ s) ... by p **→** q ≡ ¬p ⋁ q
≡ ¬(p **⋀** ¬(q ⋁ s)) ...by De Morgan's First Law
≡ ¬(p **⋀** (¬q **⋀** ¬s)) ...by De Morgan's Second Law
Any methods to get 2 more? I am having trouble.
learnmath
RAIDERS_PR
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Try replacing q ⋁ s with an implication.
KaisaPorras
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Jan 25
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KaisaPorras
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Might I suggest a hearty portion of cheese?
p→(p → (q ⋁ s))
p→(p→(p → (q ⋁ s)))
p→(p→(p→(p → (q ⋁ s))))
p→(p→(p→(p→(p → (q ⋁ s)))))
...
Alternatively,
(p → (q ⋁ s)) \^ T
or
(p → (q ⋁ s)) ⋁ F
where T is any tautology and F is any contradiction.
Jodiscohen
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Jan 25
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Jodiscohen
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