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Why does the 3 get put over the u^2v? The prior example and even on this question to the side it said it should be 1 over c^n. I’m so confused. Thanks.
LadyzjahKitty
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LadyzjahKitty
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u^-2 is the same as 1/u^2
3•u^-2 = 3/u^2
mgodard
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So why would it be 3/u^2v instead of 1/3u^2v?
In the example right before this problem it was 5u^-1 and it rewrote it as 1/5u.
nbctheinbetween
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