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What would equation for the sequence look?
thurizao
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thurizao
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Looks like you can express each term as
a_n = (n!)^2 / (4n+1)(4n-1)(4n-3)…1
Now you can use the ratio test to see if the series converges
thethinkergirls
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It seems to me test convergence need to take place
the numerator follows (N!)\^2
but the denominator has 2n-1 numbers multiplied which i don't know how it would lookk for the given series in equation
hollyshortall
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Σ from n=1 to inf of ((n!)^2 • Π from i=0 to 2n of 1/(2i+1))
sergiarola68
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