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How do u find the angle like that?
LapointeLinda
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Jan 24
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LapointeLinda
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Well arccos(–*θ*) = π – arccos(*θ*), so we have that
arccos(cos*c*) = *c* = arccos(-1/2) = π – arccos(1/2) = π – π/3
leslieannehuff
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Jan 24
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leslieannehuff
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The reference angle=pi/3.
Cosine is negative in Q2 and Q3.
This is a triangle, so C must be in Q2.
In Q2, θ=pi-θref
C=pi-pi/3=2pi/3
DavidYankovich
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Jan 24
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DavidYankovich
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