its 5. There are two ways!
1. Factoring the numerator. In this case its (x+3)(x-2), then u can cancel out x-2, leaving x+3 left. Just substitute the given limit (2), 2+3 = 5.
2. By L'Hopital's Rule, since the equation is undefined, u can get the derivative of both the numerator and denominator. Equations becomes (2x + 1)/(1) or basically just 2x +1. Substitute the 2 again, and u'll get 5. (NOTE: There are certain rules when using the L'Hopital's. It can be only be used if the equation is 0/0 or infinity/infinity. If it's not in that form, there are ways to transform which i won't discuss here.)
HOPE THIS HELPS!