Why is e^(i17π/18) = cbrt(e^(i17π/6)) wrong?

Question

At least, Wolfram Alpha says it's wrong. Could it be right and WA is wrong?

Answer 1

The cube root of e^(i17pi/6) has 3 answers, one of which is

e^(i17π/18)

Answer 2

If you look at the section called "All 3rd roots of e^(5 i π/6)" on WA, it is the second of the three solutions given.