0 like 0 dislike
0 like 0 dislike

3 Answers

0 like 0 dislike
0 like 0 dislike
Maybe because I don't know the unit circle. For the derivative question I tried using the definition of the derivative but things weren't adding uo
0 like 0 dislike
0 like 0 dislike
For the first one the derivative limit equation is
lim h>0 [f(4+h)-f(4)] / h
See which f(x) satisfied what you were given
0 like 0 dislike
0 like 0 dislike
For the second one, first recall what the Intermediate Value Theorem says.

Basically, if g(x) is a continuous function on the interval [a,b] and g(a) < 0 < g(b), then there is some value c in the interval [a,b] such that g(c) = 0.

In other words, if the function crosses the x-axis on [a,b], there is an x value that makes this possible.

We want to know which interval does NOT allow us to make this conclusion for g(x) = -3tan(x).

First, I’d calculate g(a) and g(b) for a given interval.

Then, if 0 lies in between g(a) & g(b), you discard that option (ask yourself why?) and move on to to the next one.

You’ll get the answer once you find the interval where 0 does not lie in between g(a) and g(b).

No related questions found

29.6k questions

121k answers

0 comments

33.7k users

OhhAskMe is a math solving hub where high school and university students ask and answer loads of math questions, discuss the latest in math, and share their knowledge. It’s 100% free!