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3 Answers

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Try direct comparison with 1/n^(2)

In particular, see if you can show that ln(n)^(ln(n\)) is eventually larger than n^(2).
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If you’re looking for intuition on how to notice the approach in the other comment, notice that you can rewrite the terms with a bit of algebra:

(ln n)^ln(n) = (e^ln(ln(n)) )^ln(n) = e^ln(ln(n))•ln(n) = (e^ln(n) )^ln(ln(n)) = n^ln(ln(n))

So pick n large enough so that ln(ln(n))>2
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thank you for your help

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